A bicyclist is riding to the left with a velocity of 14 m/s . After a steady gust of wind that lasts 3.5 s, the bicyclist is moving to the left with a velocity of 21 m/s Assuming the acceleration is constant, what is the acceleration of the bicyclist?
Accepted Solution
A:
He accelerated from 14 m/s to 21 m/s in 3.5s so[tex] a= \dfrac{v_1 - v_0}{t_1 - t_0} =\dfrac{21-14}{3.5} = 2 \textrm{ m/s}^2[/tex]Answer: 2 meters per second per second